f(x+h)=4x^2+5x+7

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Solution for f(x+h)=4x^2+5x+7 equation:


Simplifying
f(x + h) = 4x2 + 5x + 7

Reorder the terms:
f(h + x) = 4x2 + 5x + 7
(h * f + x * f) = 4x2 + 5x + 7
(fh + fx) = 4x2 + 5x + 7

Reorder the terms:
fh + fx = 7 + 5x + 4x2

Solving
fh + fx = 7 + 5x + 4x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-7 + fh + fx + -5x + -4x2 = 7 + 5x + 4x2 + -7 + -5x + -4x2

Reorder the terms:
-7 + fh + fx + -5x + -4x2 = 7 + -7 + 5x + -5x + 4x2 + -4x2

Combine like terms: 7 + -7 = 0
-7 + fh + fx + -5x + -4x2 = 0 + 5x + -5x + 4x2 + -4x2
-7 + fh + fx + -5x + -4x2 = 5x + -5x + 4x2 + -4x2

Combine like terms: 5x + -5x = 0
-7 + fh + fx + -5x + -4x2 = 0 + 4x2 + -4x2
-7 + fh + fx + -5x + -4x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-7 + fh + fx + -5x + -4x2 = 0

The solution to this equation could not be determined.

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